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Cell 'A' with O . P = 10 atm and T .P. =...

Cell 'A' with O . P = 10 atm and T .P. = 5 atm is in contact with a cell ' B ' having O . P = 15 atm and T. P = 12 atm . The flow of water will be :

A

From A to B

B

Equal flow

C

From B to A

D

No flow

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the direction of water flow between two cells based on their osmotic pressure (OP) and turgor pressure (TP). We will calculate the diffusion pressure deficit (DPD) for both cells and then compare them. ### Step-by-Step Solution: 1. **Identify the Given Values**: - For Cell A: - Osmotic Pressure (OP) = 10 atm - Turgor Pressure (TP) = 5 atm - For Cell B: - Osmotic Pressure (OP) = 15 atm - Turgor Pressure (TP) = 12 atm 2. **Calculate the Diffusion Pressure Deficit (DPD)**: - The formula for DPD is: \[ \text{DPD} = \text{OP} - \text{TP} \] 3. **Calculate DPD for Cell A**: - Using the values for Cell A: \[ \text{DPD}_A = \text{OP}_A - \text{TP}_A = 10 \, \text{atm} - 5 \, \text{atm} = 5 \, \text{atm} \] 4. **Calculate DPD for Cell B**: - Using the values for Cell B: \[ \text{DPD}_B = \text{OP}_B - \text{TP}_B = 15 \, \text{atm} - 12 \, \text{atm} = 3 \, \text{atm} \] 5. **Compare the DPD Values**: - DPD for Cell A = 5 atm - DPD for Cell B = 3 atm - Since DPD_A (5 atm) > DPD_B (3 atm), water will flow from the area of lower DPD to the area of higher DPD. 6. **Determine the Direction of Water Flow**: - Water will flow from Cell B to Cell A because Cell A has a higher DPD. ### Conclusion: The flow of water will be from Cell B to Cell A. ---
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