Home
Class 12
PHYSICS
A particle is projected vertically upwar...

A particle is projected vertically upwards with a speed of `16ms^-1`. After some time, when it again passes through the point of projection, its speed is found to be `8ms^-1`. It is known that the work done by air resistance is same during upward and downward motion. Then the maximum height attained by the particle is (take `g=10ms^-2`)

A

8 m

B

4.8 m

C

17.6 m

D

12.8 m

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

A particle of mass 100 g is thrown vertically upwards with a speed of 5 m//s . The work done by the force of gravity during the time the particle goes up is

A particle is projected vertically upwards with speed v_(0) . The drag force acting on it given by f_("drag")=mlambdav^(2) . The time when it is at maximum height is :

A particle is projected vertically upwards. Prove that it will be at three-fourth of its greatest height at times which are in the ratio 1: 3 .

A particle is projected vertically upward with initial velocity 25" ms"^(–1) . During third second of its motion, which of the following statement is correct ?

A projectile is projected from the ground by making an angle of 60^@ with the horizontal. After 1 s projectile makes an angle of 30^@ with the horizontal . The maximum height attained by the projectile is (Take g=10 ms^-2)

A stone is thrown vertically upwards. When stone is at a height half of its maximum height, its speed is 10 ms^-1 , then the maximum height attained by the stone is ( g= 10 ms^(-2) )

A stone is thrown vertically upwards. When stone is at a height half of its maximum height, its speed is 10 ms^-1 , then the maximum height attained by the stone is ( g= 10 ms^(-2) )

A particle is fired vertically upward with a speed of 9.8 kms^-1 . Find the maximum height attained by the particle. Radius of earth =6400 km and g at the surface =9.8ms^-2 . Consider only earth's gravitation.

A stone is projected in air. Its time of flight is 3s and range is 150m. Maximum height reached by the stone is (Take, g = 10 ms^(-2))

A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s. Then the maximum height attained by it : - (g=10 m//s^2)