If 0.5 mol of CaBr(2) is mixed with 0.2 ...

If 0.5 mol of `CaBr_(2)` is mixed with 0.2 mol of `K_(3) PO_(4)`, the maximum nubmer of moles of `Ca_(3) (PO_(4))_(2)` that can be formed is:
a. 0.1 b. 0.2 c. 0.5 d.0.7

A

0.7

B

0.5

C

0.03

D

`0.10`

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The correct Answer is:

D

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