In a fully turgid cells, the values of DPD,OP and TP will be

Options

A. DPD = 10 atm, OP = 15 atm , TP = 5 atm
B. DPD = 5 atm, OP = 12 atm , TP = 7 atm
C. DPD = 2 atm, OP = 7 atm , TP = 5 atm
D. DPD = 0 atm, OP = 15 atm , TP = 15 atm

Answer

To solve the question regarding the values of DPD (Diffusion Pressure Deficit), OP (Osmotic Pressure), and TP (Turgor Pressure) in a fully turgid cell, we can follow these steps:

### Step 1: Understand the Definitions
- **Osmotic Pressure (OP)**: This is the pressure required to prevent the flow of water into a solution via osmosis. It is a measure of the tendency of water to move into a cell.
- **Turgor Pressure (TP)**: This is the pressure exerted by the fluid (usually water) inside the cell against the cell wall. It helps maintain the structure of the cell.
- **Diffusion Pressure Deficit (DPD)**: This is calculated as the difference between osmotic pressure and turgor pressure. The formula is:
\[ DPD = OP - TP \]

### Step 2: Analyze a Fully Turgid Cell
In a fully turgid cell:
- The cell is filled with water, and the pressure inside the cell (turgor pressure) is at its maximum.
- The osmotic pressure is also at its maximum because the concentration of solutes inside the cell is high.

### Step 3: Determine the Values
1. **DPD**: In a fully turgid cell, the cell has reached equilibrium with its surroundings, meaning it is not absorbing more water. Thus, the DPD will be:
\[ DPD = OP - TP = 0 \]
This indicates that the osmotic pressure equals the turgor pressure.

2. **OP and TP**: Since DPD is 0, we can conclude that:
\[ OP = TP \]
If we assume that both OP and TP are equal to 15 atmospheres (a common value for fully turgid cells), we have:
\[ OP = 15 \text{ atmospheres}, \quad TP = 15 \text{ atmospheres} \]

### Step 4: Final Values
Thus, in a fully turgid cell:
- DPD = 0 atmospheres
- OP = 15 atmospheres
- TP = 15 atmospheres

### Conclusion
The correct option for the values of DPD, OP, and TP in a fully turgid cell is:
- DPD = 0 atmospheres
- OP = 15 atmospheres
- TP = 15 atmospheres