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In the options given below, let E denote...

In the options given below, let `E` denote the rest mass energy of a nucleus and `n` a neutron. The correct option is:

A

`E(._(92)^(236)U)gtE(._(53)^(137)I)+E(._39^(97)Y)+2E(n)`

B

`E(._(92)^(236)U)ltE(._(53)^(137)I)+E(._39^(97)Y)+2E(n)`

C

`E(._(92)^(236)U)ltE(._(56)^(140)Ba)+E(._36^(94)Kr)+2E(n)`

D

`E(._(92)^(235)U)=E(._(56)^(140)Ba)+E(._36^(94)Kr)+2E(n)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the rest mass energy of a nucleus and a neutron, we will analyze the given information step by step. ### Step 1: Understand the Concepts - **Rest Mass Energy (E)**: This is the energy equivalent of the mass of a particle or nucleus at rest, given by the equation \(E = mc^2\), where \(m\) is the mass and \(c\) is the speed of light. - **Fission Process**: This is a nuclear reaction in which a heavy nucleus splits into smaller nuclei, releasing energy. ### Step 2: Analyze the Given Information We are given that: - The rest mass energy of uranium (U) is compared to the rest mass energies of iodine (I), uranium (U), and two neutrons (n). - The expression can be represented as: \[ E_U > E_I + E_U + 2E_n \] where \(E_U\) is the rest mass energy of uranium, \(E_I\) is the rest mass energy of iodine, and \(E_n\) is the rest mass energy of a neutron. ### Step 3: Apply the Concept of Mass Defect In a fission reaction: - The mass defect (\(\Delta m\)) occurs because the total mass of the products (smaller nuclei and neutrons) is less than the mass of the original nucleus (uranium). - The energy released in the fission process can be calculated using: \[ E = \Delta m \cdot c^2 \] - This means that the rest mass energy of the original heavy nucleus (uranium) is greater than the total rest mass energy of the products (iodine, uranium, and neutrons). ### Step 4: Evaluate the Options - **Option A**: \(E_U > E_I + E_U + 2E_n\) — This is correct as explained above. - **Option B**: \(E_U < E_I + E_U + 2E_n\) — This is incorrect because the original nucleus has more energy. - **Option C**: \(E_U = E_I + E_U + 2E_n\) — This is also incorrect as it implies no energy is released. - **Option D**: Any other statement that contradicts the above conclusions. ### Conclusion The only correct option is **Option A**: \(E_U > E_I + E_U + 2E_n\).
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