A mass of 6xx10^24 kg (equal to the mass...

A mass of `6xx10^24` kg (equal to the mass of the earth) is to be compressed in a sphere in such a way that the escape velocity from its surface is `3xx10^8ms^-1`. What should be the radius of the sphere?

9 km

9 m

9 cm

9 mm

Text Solution

Verified by Experts

The correct Answer is:

Similar Questions

Explore conceptually related problems

A planet has mass equal to mass of the earth but radius one fourth of radius of the earth . Then escape velocity at the surface of this planet will be

Find the escape velocity of a body from the surface of the earth. Given radius of earth = 6.38 xx 10^(6) m .

A planet in a distant solar systyem is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11kms^(-1) , the escape velocity from the surface of the planet would be

Calculate the escape velocity from the moon. The mass of the moon =7.4xx10^22kg and radius of the moon =1740km

Mass and radius of a planet are two times the value of earth. What is the value of escape velocity from the surface of this planet?

The mass of a planet is six times that of the earth. The radius of the planet is twice that of the earth. If the escape velocity from the earth is v , then the escape velocity from the planet is:

What should be the radius of a planet with mass equal to that of earth and escape velocity on its surface is equal to the velocity of light. Given that mass of earth is M=6xx10^(24)kg .

Calculate the escape velocity from the surface of a planet of mass 14.8 xx 10^(22) kg. It is given that radius of the planet is 3.48 xx 10^(6) m.

A mass of `6xx10^24` kg (equal to the mass of the earth) is to be compressed in a sphere in such a way that the escape velocity from its surface is `3xx10^8ms^-1`. What should be the radius of the sphere?

Text Solution

Similar Questions

Recommended Questions