Home
Class 12
PHYSICS
What is the binding energy per nucleon o...

What is the binding energy per nucleon of `""_(6)C^(12)` nucleus?
Given, mass of `C^(12)(m_c)=12.000u`
Mass of proton `(m_(p))=1.0078u`
Mass of neutron `(m_(n))=1.0087u`
and 1 amu `=931.4(MeV)/(c^(2))`

A

5.26 MeV

B

10.11 MeV

C

15.65 MeV

D

7.68 MeV

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

What is the binding energy per nucleon of _(6)C^(12) nucleus? Given , mass of C^(12) (m_(c))_(m) = 12.000 u Mass of proton m_(p) = 1.0078 u Mass of neutron m_(n) = 1.0087 u and 1 amu = 931.4 MeV

What is the binding energy per nucleon in ._2He^4 Given , Mass of ._2He^4 =4.002604 amu Mass of proton =1.007825 amu Mass of neutron =1.008665 amu

What is the binding energy per nucleon in ._2He^4 Given , Mass of ._2He^4 =4.002604 amu Mass of proton =1.007825 amu Mass of neutron =1.008665 amu

Calculate the binding energy per nucleon of ._17^35Cl nucleus. Given that mass of ._17^35Cl nucleus = 34.98000 u, mass of proton = 1.007825 u, mass of neutron = 1.008665 u and 1 u is equivalent to 931 Mev.

Find the Binding energy per neucleon for ""_(50)^(120)Sn Mass of proton m_(p)=1.00783U , mass of neutron m_(n)=1.00867U and mass of tin nucleus m_(Sn)=119.902199U . (take 1 U = 931 MEV)

Calculate the binding energy per nucleon of ._(20)^(40)Ca . Given that mass of ._(20)^(40)Ca nucleus = 39.962589 u , mass of proton = 1.007825 u . Mass of Neutron = 1.008665 u and 1 u is equivalent to 931 MeV .

Calculate mass defect and binding energy per nucleon of ""_(10)^(20)Ne , given Mass of ""_(10)^(20)Ne = 19.992397 u Mass of ""_1^(1)H = 1.007825 u Mass of on = ""_(0)^(1)1.008665 u

Calculate the average binding energy per nucleon of ._(41)^(93)Nb having mass 9.2.906 u..

Calculate binding energy of oxygen nucleus (""_(8)^(16)O) from the data given below: Mass of a proton m_(p) = 1.007825u Mass of neutron m_(n) = 1.008665u Mass of (""_(8)^(16)O)m_(o) = 15.994915 u

Binding energy per nucleon of ._50Sn^120 approximately will be. [ Atomic mass of ._50Sn^120 is 120.500 u and that of ._1H^1 is 1.007u . mass of neutron = 1.008u , 1u= 931 Mev ]