Benzene diazonium chloride on reaction with aniline in the presence of dilute hydrochloric acid gives :

Options

A.
B.
C.
D.

Answer

To solve the question, we need to analyze the reaction between benzene diazonium chloride and aniline in the presence of dilute hydrochloric acid.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are benzene diazonium chloride (C6H5N2Cl) and aniline (C6H5NH2).

2. **Understand the Reaction Conditions**:
- The reaction occurs in the presence of dilute hydrochloric acid (HCl). This acid helps to maintain the stability of the diazonium salt.

3. **Mechanism of the Reaction**:
- Benzene diazonium chloride (C6H5N2Cl) is a strong electrophile due to the presence of the diazonium group (N2+).
- Aniline, which has an amino group (-NH2), acts as a nucleophile. The lone pair of electrons on the nitrogen atom of aniline can attack the electrophilic diazonium ion.

4. **Formation of the Coupling Product**:
- When aniline reacts with benzene diazonium chloride, the amino group of aniline attacks the diazonium ion, leading to the formation of a coupling product.
- The reaction can be represented as follows:
\[ C6H5N2Cl + C6H5NH2 \rightarrow C6H5-N=N-C6H5-NH2 + HCl \]
- The product formed is a substituted azo compound, specifically an azo dye, which has the structure:
\[ C6H5-N=N-C6H5-NH2 \]
- This product is known as an azo compound due to the presence of the -N=N- (azo) group.

5. **Conclusion**:
- The final product of the reaction is an azo compound formed by the coupling of aniline with benzene diazonium chloride.

### Final Answer:
The reaction of benzene diazonium chloride with aniline in the presence of dilute hydrochloric acid gives an azo compound.