The net requirement of assimilatory power for the formation of 6 hexose molecules in maize plant is

Options

A. 72 ATP , 48 NADPH
B. 90 ATP, 60 NADPH
C. 108 ATP , 72 NADPH
D. 180 ATP , 72 NADPH

Answer

To solve the problem regarding the net requirement of assimilatory power for the formation of 6 hexose molecules in maize plants, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Requirements for One Hexose Molecule**:
- In maize plants (which are C4 plants), the formation of one hexose molecule requires:
- 30 ATP (adenosine triphosphate)
- 12 NADPH (nicotinamide adenine dinucleotide phosphate)

2. **Calculate the Requirements for Six Hexose Molecules**:
- Since we need to find the requirements for 6 hexose molecules, we multiply the requirements for one hexose molecule by 6:
- ATP requirement:
\[ 30 \, \text{ATP} \times 6 = 180 \, \text{ATP} \]
- NADPH requirement:
\[ 12 \, \text{NADPH} \times 6 = 72 \, \text{NADPH} \]

3. **Final Result**:
- Therefore, the net requirement of assimilatory power for the formation of 6 hexose molecules in maize plant is:
- 180 ATP
- 72 NADPH

4. **Select the Correct Option**:
- Based on the calculations, the correct answer is option number 4.