The structure of compound, which is formed by `sP^3`d hybridization will be

Options

A. Angular
B. Planar
C. Pyramidal
D. Trigonal bipyramidal

Answer

To determine the structure of a compound formed by \( sp^3d \) hybridization, we can follow these steps:

### Step 1: Understand Hybridization
Hybridization is the mixing of atomic orbitals to form new hybrid orbitals. The \( sp^3d \) hybridization involves one s orbital, three p orbitals, and one d orbital.

### Step 2: Identify the Geometry
The \( sp^3d \) hybridization leads to a specific molecular geometry. In this case, it corresponds to a trigonal bipyramidal arrangement. This means that there are five regions of electron density around the central atom.

### Step 3: Analyze Electron Pair Geometry
In a trigonal bipyramidal structure, there are two distinct types of positions for the bonded atoms:
- Three atoms occupy the equatorial positions (in a plane).
- Two atoms occupy the axial positions (above and below the equatorial plane).

### Step 4: Consider Lone Pairs
The question states that there are no lone pairs on the central atom. This means that all five positions are occupied by bonding pairs of electrons, confirming the trigonal bipyramidal geometry.

### Step 5: Conclusion
Based on the above analysis, the structure of a compound formed by \( sp^3d \) hybridization is indeed trigonal bipyramidal.

### Final Answer
The structure of the compound formed by \( sp^3d \) hybridization is **trigonal bipyramidal**.

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