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Dimensional formula of the physical quan...

Dimensional formula of the physical quantity, resistance is

A

`[ML^2T^(-3)A^(-2)]`

B

`[ML^(-1)T^(3)A^(-1)]`

C

`[ML^(2)T^(-2)K^(-1)]`

D

`[ML^(-2)T^(-3)K^(2)]`

Text Solution

AI Generated Solution

The correct Answer is:
To find the dimensional formula of resistance, we can use Ohm's law, which states that: \[ V = I \cdot R \] From this, we can express resistance \( R \) as: \[ R = \frac{V}{I} \] ### Step 1: Determine the dimensions of Voltage (V) Voltage can be defined in terms of electric field (E) and distance (d): \[ V = E \cdot d \] The electric field \( E \) can be expressed as: \[ E = \frac{F}{Q} \] Where: - \( F \) is force (with dimensions \( [M L T^{-2}] \)) - \( Q \) is charge (with dimensions \( [A T] \)) Now substituting for \( E \): \[ V = \frac{F}{Q} \cdot d = \frac{[M L T^{-2}]}{[A T]} \cdot [L] \] This simplifies to: \[ V = \frac{M L^2}{A T^2} \] ### Step 2: Determine the dimensions of Current (I) Current \( I \) is defined as charge per unit time: \[ I = \frac{Q}{T} \] The dimension of charge \( Q \) is \( [A T] \), thus: \[ I = \frac{[A T]}{[T]} = [A] \] ### Step 3: Substitute the dimensions into the resistance formula Now substituting the dimensions of \( V \) and \( I \) into the resistance formula: \[ R = \frac{V}{I} = \frac{[M L^2 T^{-2} A^{-1}]}{[A]} \] This simplifies to: \[ R = [M L^2 T^{-2} A^{-2}] \] ### Final Step: Write the dimensional formula for resistance Thus, the dimensional formula for resistance \( R \) is: \[ R = [M L^2 T^{-3} A^{-2}] \] ### Answer The dimensional formula of resistance is: \[ [M L^2 T^{-3} A^{-2}] \] ---
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