`6.02xx10^(20)` molecules of urea are present in 100 ml of its solution. The concentration of solution is :

Options

A. 0.01 M
B. 0.001 M
C. 0.1 M
D. 0.02 M

Answer

To find the concentration of the urea solution, we will follow these steps:

### Step 1: Calculate the number of moles of urea
We are given the number of molecules of urea as \(6.02 \times 10^{20}\). To convert this to moles, we use Avogadro's number (\(N_A = 6.02 \times 10^{23}\) molecules/mol).

\[ \text{Number of moles (n)} = \frac{\text{Number of molecules}}{N_A} = \frac{6.02 \times 10^{20}}{6.02 \times 10^{23}} = 1 \times 10^{-3} \text{ moles} \]

### Step 2: Convert the volume of the solution from mL to L
The volume of the solution is given as 100 mL. We need to convert this to liters:

\[ \text{Volume (V)} = 100 \text{ mL} = 0.1 \text{ L} \]

### Step 3: Calculate the concentration of the solution
Concentration (C) is defined as the number of moles of solute per unit volume of solution in liters:

\[ C = \frac{n}{V} = \frac{1 \times 10^{-3} \text{ moles}}{0.1 \text{ L}} = 10^{-2} \text{ moles/L} \]

### Step 4: Convert the concentration to a more understandable format
\[ C = 10^{-2} \text{ moles/L} = 0.01 \text{ moles/L} \]

Thus, the concentration of the urea solution is \(0.01 \text{ moles/L}\).

### Final Answer
The concentration of the solution is \(0.01 \text{ moles/L}\) or \(10^{-2} \text{ moles/L}\).