For a transistor working as common base amplifier, the emitter current is 0.72 mA. The. Current gain is 0.96. The collector current is

Options

A. `0.96xx0.72mA`
B. `(0.96)/(0.72)mA`
C. `0.96-0.72mA`
D. `7.2A-2xx0.96mA`

Answer

To find the collector current (\(I_C\)) in a common base amplifier, we can use the relationship between the emitter current (\(I_E\)) and the current gain (\(\alpha\)). The current gain in a common base configuration is defined as:

\[ \alpha = \frac{I_C}{I_E} \]

Where:
- \(I_C\) is the collector current,
- \(I_E\) is the emitter current.

Given:
- Emitter current, \(I_E = 0.72 \, \text{mA}\)
- Current gain, \(\alpha = 0.96\)

We can rearrange the formula to find the collector current:

\[ I_C = \alpha \times I_E \]

Now, substituting the given values:

\[ I_C = 0.96 \times 0.72 \, \text{mA} \]

Calculating the product:

\[ I_C = 0.6912 \, \text{mA} \]

Thus, the collector current is:

\[ I_C \approx 0.69 \, \text{mA} \]

### Final Answer:
The collector current is approximately \(0.69 \, \text{mA}\).

---