Hydrogen peroxide oxidises [Fe(CN)(6)]^(...

Hydrogen peroxide oxidises `[Fe(CN)_(6)]^(4-)` to `[Fe(CN)_(6)]^(3-)` in acidic medium but reduces `[Fe(CN)_(6)]^(3-)` to `[Fe(CN)_(6)]^(4-)` in alkaline medium. The other products formed are, respectively

A

`H_2O and (H_2O+OH^(-))`

B

`(H_2O+O_2) and H_2O`

C

`(H_2O+O_2) and (H_2O+OH^(-))`

D

`H_2O and (H_2O+O_2)`

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The correct Answer is:

D

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[Fe(H_(2)O)_(6)]^(3+) and [Fe(CN)_(6)]^(3-) differ in

[Fe(H_(2)O)_(6)]^(2+) and [Fe(CN)_(6)]^(4-) differ in :

K_(3)[Fe(CN)_(6)]+FeCl_(3) to Fe[Fe(CN)_(6)]darr

Fe(CN)_(2)darr+4KCN to K_(4)[Fe(CN)_(6)]

3KCN+Fe(CN)_(3)darr to K_(3)[Fe(CN)_(6)]

The complex ion [Fe(CN)_(6)]^(4-) contains:

Fe(CN)_(2)darr+KCN to K_(3)Fe(CN)_(6)

4KCN+Fe(CN)_(2)darr to K_(4)[Fe(CN)_(6)]