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Arrange in decreasing order of + R power...

Arrange in decreasing order of + R power in the given groups
(1) `-NH_2`
(2) `-O^(Theta)`
(3) `-OH`
(4) `-NHCOCH_3`

A

`2gt1gt3gt4`

B

`2gt3gt1gt4`

C

`1gt2gt3gt4`

D

`3gt2gt1gt4`

Text Solution

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The correct Answer is:
To arrange the given groups in decreasing order of +R (resonance donating) power, we need to analyze the ability of each group to donate electrons through resonance. The groups we have are: 1. `-NH2` (Amino group) 2. `-O^(Theta)` (Ether group) 3. `-OH` (Hydroxyl group) 4. `-NHCOCH3` (Acetamido group) ### Step-by-Step Solution: **Step 1: Analyze each group for resonance donation.** - **`-NH2`**: The amino group has a lone pair of electrons on the nitrogen atom that can participate in resonance. It is a strong +R group due to its ability to donate electrons effectively. - **`-O^(Theta)`**: The ether group has two lone pairs of electrons on the oxygen atom. This allows it to donate electrons through resonance, making it a very strong +R group. - **`-OH`**: The hydroxyl group also has a lone pair on the oxygen that can participate in resonance. However, it is less effective than the ether group because it has only one lone pair available for resonance donation. - **`-NHCOCH3`**: The acetamido group has nitrogen that can donate its lone pair, but the carbonyl (C=O) present in the group can withdraw electron density through resonance. This makes it less effective as a +R group compared to the others. **Step 2: Rank the groups based on their +R power.** 1. `-O^(Theta)` (Ether) - Strongest +R group due to two lone pairs. 2. `-NH2` (Amino) - Second strongest +R group due to one lone pair. 3. `-OH` (Hydroxyl) - Third strongest +R group due to one lone pair but less effective than `-NH2`. 4. `-NHCOCH3` (Acetamido) - Weakest +R group due to resonance withdrawal by the carbonyl. ### Final Order: Thus, the decreasing order of +R power is: **`-O^(Theta) > -NH2 > -OH > -NHCOCH3`**
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