In given reaction [X] and [Y] respectively are `CH_3-overset(O)overset(||)C-O-underset(CH_3)underset(|)overset(CH_3)overset(|)C-CH_3overset(Na//C_2H_5OH)rarr(X)+(Y)`

Options

A. `CH_3-CH_2-OH and CH_3-underset(CH_3)underset(|)overset(CH_3)overset(|)C-OH`
B. `CH_3-CH_2-OH and CH_3-underset(CH_3) underset(|)C-CH_2`
C. `CH_2=CH_2 and CH_3-underset(CH_3)underset(|)overset(CH_3)overset(|)C-OH`
D. `CH_3-CH_2-underset(CH_3)underset(|)overset(CH_3)overset(|)O-C-CH_3`

Answer

To solve the question, we need to identify the products X and Y formed from the reaction of the given compound with sodium in ethanol (Na/C2H5OH). The compound is an ester, and we will analyze the reaction step by step.

### Step-by-Step Solution:

1. **Identify the Structure of the Compound**:
The compound given is CH3C(=O)O(CH3)3C-CH3. This can be recognized as an ester where CH3C(=O) is the acyl part and (CH3)3C-CH3 is the alkyl part.

2. **Recognize the Reaction Type**:
The reaction involves sodium (Na) in ethanol (C2H5OH), which indicates a reduction reaction where the ester will be converted into an alcohol and a carbonyl compound.

3. **Mechanism of the Reaction**:
- Sodium donates electrons to the carbonyl carbon of the ester, forming a radical intermediate.
- This radical intermediate can then react with ethanol to form an alcohol and a carbanion.
- The carbanion can further react with another equivalent of ethanol, leading to the formation of the final products.

4. **Formation of Products**:
- The first product (X) will be a primary alcohol formed from the acyl part of the ester. This is CH3C(=O)OH (which is acetic acid).
- The second product (Y) will be the alcohol formed from the alkyl part, which is (CH3)3C-OH (tert-butyl alcohol).

5. **Final Products**:
Therefore, the products of the reaction are:
- X = CH3C(=O)OH (acetic acid)
- Y = (CH3)3C-OH (tert-butyl alcohol)

### Conclusion:
The products formed in the reaction are:
- X = CH3C(=O)OH
- Y = (CH3)3C-OH