A transistor have a `beta` a equal to 80 has a change in base current of `250mu` ampere, then the change in collector current is

Options

A. `170 muA`
B. `330 muA`
C. `3.125 muA`
D. 20 mA

Answer

To solve the problem, we need to find the change in collector current (ΔIc) given the change in base current (ΔIb) and the transistor's beta (β).

### Step-by-Step Solution:

1. **Understand the relationship between collector current and base current**:
The relationship is given by the formula:
\[ \beta = \frac{\Delta I_c}{\Delta I_b} \]
where:
- \( \Delta I_c \) = change in collector current
- \( \Delta I_b \) = change in base current
- \( \beta \) = current gain of the transistor

2. **Rearranging the formula to find ΔIc**:
We can rearrange the formula to express ΔIc in terms of ΔIb and β:
\[ \Delta I_c = \beta \times \Delta I_b \]

3. **Substituting the given values**:
From the problem, we have:
- \( \beta = 80 \)
- \( \Delta I_b = 250 \, \mu A = 250 \times 10^{-6} \, A \)

Now substituting these values into the equation:
\[ \Delta I_c = 80 \times (250 \times 10^{-6}) \]

4. **Calculating ΔIc**:
\[ \Delta I_c = 80 \times 250 \times 10^{-6} \]
\[ = 20000 \times 10^{-6} \, A \]
\[ = 20 \times 10^{-3} \, A \]
\[ = 20 \, mA \]

5. **Final Answer**:
The change in collector current (ΔIc) is:
\[ \Delta I_c = 20 \, mA \]