If NaCl is doped with 10^(-4)"mol"% of s...

If `NaCl` is doped with `10^(-4)"mol"%` of `srCl_(2)`, the concentration of cation vacancies will be `(N_(A)=6.023xx10^(23)"mol"^(-1))`

A

`6.02xx10^(16) mol^(-1)`

B

`6.02xx10^(17) mol^(-1)`

C

`6.02xx10^(14) mol^(-1)`

D

`6.02xx10^(15) mol^(-1)`

Verified by Experts

The correct Answer is:

B

Similar Questions

Explore conceptually related problems

If NaCl is doped with 10^(-4)mol% of SrCl_(2) the concentration of cation vacancies will be (N_(A)=6.02xx10^(23)mol^(-1))

If NaCl is doped with 10^(-8)mol% of SrCl_(2) the concentration of cation vacancies will be (N_(A)=6.02xx10^(23)mol^(-1))

If NaCl is doped with 10^(-3) mol% of SrCl_(2) , what is the concentration of cation vacancies?

NaCl is doped with 2xx10^(-3) mol % SrCl_2 , the concentration of cation vacancies is

If NaCl is doped with 10^(-2) mol % SrCl_2 , what is the concentration of cation vacancies?

If NaCl is doped with 10^(-3) mol % SrCl_2 , what is the concentration of cation vacancies?

If NaCl is doped with 10^(-3) mol% GaCl_(3) , what is the concentration of the cation vacancies?