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When 1 L of CO2 is heated with graphite ...

When 1 L of `CO_2` is heated with graphite , the volume of the gases collected is 1.5 L. Calculate the number of moles of CO produced at STP

A

`1/(11.2)`

B

`28/22.4`

C

`1/(22.4)`

D

`14/(22.4)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of calculating the number of moles of CO produced when 1 L of CO₂ is heated with graphite, we can follow these steps: ### Step 1: Understand the Reaction When carbon dioxide (CO₂) is heated with graphite (carbon), it can produce carbon monoxide (CO) according to the reaction: \[ \text{CO}_2 + \text{C} \rightarrow 2 \text{CO} \] ### Step 2: Set Up the Initial Conditions We start with 1 L of CO₂. According to the problem, after the reaction, the total volume of gases collected is 1.5 L. ### Step 3: Define Variables Let \( x \) be the volume of CO₂ that reacts. Since 1 L of CO₂ is present initially, the volume of CO₂ left after the reaction will be \( 1 - x \) L. From the stoichiometry of the reaction, for every 1 L of CO₂ that reacts, 2 L of CO is produced. Therefore, the volume of CO produced will be \( 2x \) L. ### Step 4: Write the Volume Equation The total volume of gases after the reaction is the sum of the remaining CO₂ and the produced CO: \[ (1 - x) + 2x = 1.5 \] ### Step 5: Simplify the Equation Now, simplify the equation: \[ 1 - x + 2x = 1.5 \] \[ 1 + x = 1.5 \] ### Step 6: Solve for \( x \) Subtract 1 from both sides: \[ x = 1.5 - 1 \] \[ x = 0.5 \, \text{L} \] ### Step 7: Calculate the Volume of CO Produced Now, we can find the volume of CO produced: \[ \text{Volume of CO} = 2x = 2 \times 0.5 = 1 \, \text{L} \] ### Step 8: Calculate the Number of Moles of CO at STP At standard temperature and pressure (STP), 1 mole of gas occupies 22.4 L. Therefore, the number of moles of CO produced can be calculated as: \[ \text{Number of moles of CO} = \frac{\text{Volume of CO}}{22.4} = \frac{1 \, \text{L}}{22.4 \, \text{L/mol}} \] ### Step 9: Final Calculation Calculating the number of moles: \[ \text{Number of moles of CO} = \frac{1}{22.4} \approx 0.04464 \, \text{moles} \] ### Conclusion The number of moles of CO produced at STP is approximately 0.04464 moles. ---
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