Refer the given equation.
`2(C_(51)H_(98)O_(6)) + 145O_(2) rarr 102CO_(2) +98H_(2)O +` Energy The RQ in this case is

Options

A. Palmitin, R.Q = 0.9
B. Tripalmitin , R.Q. = 0.7
C. Palmitin, R.Q = 1
D. Tripalmitin , R.Q. = 0.2

Answer

To solve the problem, we need to calculate the Respiratory Quotient (RQ) using the given equation. The RQ is defined as the ratio of the volume of carbon dioxide (CO₂) produced to the volume of oxygen (O₂) consumed during respiration.

### Step-by-Step Solution:

1. **Identify the Products and Reactants:**
From the equation provided:
\[ 2(C_{51}H_{98}O_{6}) + 145O_{2} \rightarrow 102CO_{2} + 98H_{2}O + \text{Energy} \]
- Products: 102 CO₂ and 98 H₂O
- Reactants: 145 O₂

2. **Calculate the RQ:**
The formula for RQ is:
\[ RQ = \frac{\text{Volume of CO}_2 \text{ produced}}{\text{Volume of O}_2 \text{ consumed}} \]
Substituting the values from the equation:
\[ RQ = \frac{102 \text{ CO}_2}{145 \text{ O}_2} \]

3. **Perform the Calculation:**
Now, we perform the division:
\[ RQ = \frac{102}{145} \approx 0.7034 \]
Rounding this value gives us approximately 0.7.

4. **Interpret the RQ Value:**
- An RQ of 1 indicates carbohydrate metabolism.
- An RQ less than 1 indicates fat metabolism.
- An RQ of approximately 0.7 suggests that the substrate being metabolized is likely a fat.

### Conclusion:
Thus, the RQ in this case is approximately 0.7, indicating that the substrate is fat.