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A truck of mass 10 metric ton runs at 3m...

A truck of mass 10 metric ton runs at `3ms^(-1)` along a level track and collides with a loaded truck of mass 20 metric ton, standing at rest. If the trucks couple together , the common speed after the collision is

A

`1 ms ^(-1)`

B

`0.1 ms ^(-1)`

C

`0.5 ms ^(-1)`

D

`0.3 ms ^(-1)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the principle of conservation of momentum. Here's the detailed solution: ### Step 1: Identify the masses and velocities before the collision - Mass of the first truck (m1) = 10 metric tons = 10,000 kg (since 1 metric ton = 1,000 kg) - Velocity of the first truck (u1) = 3 m/s - Mass of the second truck (m2) = 20 metric tons = 20,000 kg - Velocity of the second truck (u2) = 0 m/s (since it is at rest) ### Step 2: Calculate the initial momentum of the system The initial momentum (P_initial) of the system can be calculated using the formula: \[ P_{\text{initial}} = m_1 \cdot u_1 + m_2 \cdot u_2 \] Substituting the values: \[ P_{\text{initial}} = (10,000 \, \text{kg} \cdot 3 \, \text{m/s}) + (20,000 \, \text{kg} \cdot 0 \, \text{m/s}) \] \[ P_{\text{initial}} = 30,000 \, \text{kg m/s} + 0 \] \[ P_{\text{initial}} = 30,000 \, \text{kg m/s} \] ### Step 3: Calculate the final momentum of the system After the collision, both trucks couple together and move with a common velocity (V). The total mass after the collision is: \[ m_{\text{total}} = m_1 + m_2 = 10,000 \, \text{kg} + 20,000 \, \text{kg} = 30,000 \, \text{kg} \] The final momentum (P_final) of the system is given by: \[ P_{\text{final}} = m_{\text{total}} \cdot V \] \[ P_{\text{final}} = 30,000 \, \text{kg} \cdot V \] ### Step 4: Apply the conservation of momentum According to the conservation of momentum: \[ P_{\text{initial}} = P_{\text{final}} \] \[ 30,000 \, \text{kg m/s} = 30,000 \, \text{kg} \cdot V \] ### Step 5: Solve for V To find the common velocity (V), we can rearrange the equation: \[ V = \frac{30,000 \, \text{kg m/s}}{30,000 \, \text{kg}} \] \[ V = 1 \, \text{m/s} \] ### Conclusion The common speed after the collision is **1 m/s**.
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