20.8g of `BaCI_2` on reaction with 9.8g of `H_2SO_4` produces 7.3 g of HCI and some amount of `BaSO_4` The amount of `BaSO_4` formed is

Options

A. 23.3 g
B. 20.8 g
C. 9.8 g
D. 10.4 g

Answer

To find the amount of BaSO₄ formed from the reaction of BaCl₂ with H₂SO₄, we can follow these steps:

### Step 1: Write the balanced chemical equation
The balanced chemical equation for the reaction is:
\[ \text{BaCl}_2 + \text{H}_2\text{SO}_4 \rightarrow \text{BaSO}_4 + 2\text{HCl} \]

### Step 2: Calculate the number of moles of BaCl₂
To find the number of moles of BaCl₂, we use the formula:
\[ \text{Number of moles} = \frac{\text{Given weight}}{\text{Molar mass}} \]

The molar mass of BaCl₂ is calculated as follows:
- Molar mass of Ba = 137 g/mol
- Molar mass of Cl = 35.5 g/mol (and there are 2 Cl atoms)

Thus, the molar mass of BaCl₂ = 137 + (2 × 35.5) = 137 + 71 = 208 g/mol.

Now, substituting the values:
\[ \text{Number of moles of BaCl}_2 = \frac{20.8 \text{ g}}{208 \text{ g/mol}} = 0.1 \text{ moles} \]

### Step 3: Determine the number of moles of BaSO₄ produced
From the balanced equation, we can see that 1 mole of BaCl₂ produces 1 mole of BaSO₄. Therefore, the number of moles of BaSO₄ produced is also 0.1 moles.

### Step 4: Calculate the mass of BaSO₄ formed
To find the mass of BaSO₄ produced, we again use the number of moles and the molar mass:
\[ \text{Mass} = \text{Number of moles} \times \text{Molar mass} \]

The molar mass of BaSO₄ is calculated as follows:
- Molar mass of Ba = 137 g/mol
- Molar mass of S = 32 g/mol
- Molar mass of O = 16 g/mol (and there are 4 O atoms)

Thus, the molar mass of BaSO₄ = 137 + 32 + (4 × 16) = 137 + 32 + 64 = 233 g/mol.

Now, substituting the values:
\[ \text{Mass of BaSO}_4 = 0.1 \text{ moles} \times 233 \text{ g/mol} = 23.3 \text{ g} \]

### Final Answer
The amount of BaSO₄ formed is **23.3 g**.

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