Home
Class 12
PHYSICS
A charged particle enters a unifrom mag...

A charged particle enters a unifrom magnetic field with velocity vector at an angle of `45^(@)` with the magnetic field . The pitch of the helical path followed by the particles is `rho` . The radius of the helix will be

A

`p/(sqrt(2)pi)`

B

`sqrt(2)p`

C

`p/(2pi)`

D

`(sqrt(2)p)/(pi)`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

When a charged particle enters a uniform magnetic field its kinetic energy

A charged particle enters a uniform magnetic field perpendicular to it. The magnetic field

A charged particle moves in a uniform magnetic field. The velocity of the particle at some instant makes an acute angle with the magnetic field. The path of the particle will be

A charged particle enters in a magnetic field B with its initial velocity making an angle of 45° with B. The path of the particle will be

If a charged particle enters perpendicular in the uniform magnetic field then

A charged particle enters a region of uniform magnetic field at an angle of 85^@ to the magnetic line of force. The path of the particle is a circle. Is this statement true or false?

A beam of protons with a velocity of 4 X 10 ^5 ms^(-1) enters a uniform magnetic field of 0.3 T. The velocity makes an angle of 60^@ with the magnetic field. Find the radius of the helicla path taken by the proton beam and the pitch of the helix.

A beam of protons with a velocity of 4 X 10 ^5 ms^(-1) enters a uniform magnetic field of 0.3 T. The velocity makes an angle of 60^@ with the magnetic field. Find the radius of the helicla path taken by the proton beam and the pitch of the helix.

A beam of protons with a velocity of 4 X 10 ^5 ms^(-1) enters a uniform magnetic field of 0.3 T. The velocity makes an angle of 60^@ with the magnetic field. Find the radius of the helicla path taken by the proton beam and the pitch of the helix.

A beam of protons enters a uniform magnetic field of 0.3T with velocity of 4xx10^5m//s in a direction making an angle of 60^(@) with the direction of magnetic field. The path of motion of the particle will be