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How many amino acids will be coded by fo...

How many amino acids will be coded by following intron?
AUG CCC CAC CAC UUA UAU AUA UAA GAC AAA GCG UUU CAU UAA

A

7

B

8

C

10

D

11

Text Solution

AI Generated Solution

The correct Answer is:
To determine how many amino acids will be coded by the given mRNA sequence, we will follow these steps: ### Step 1: Identify the mRNA sequence The provided mRNA sequence is: ``` AUG CCC CAC CAC UUA UAU AUA UAA GAC AAA GCG UUU CAU UAA ``` ### Step 2: Break the sequence into codons We will divide the sequence into codons (groups of three nucleotides): ``` AUG | CCC | CAC | CAC | UUA | UAU | AUA | UAA | GAC | AAA | GCG | UUU | CAU | UAA ``` ### Step 3: Identify the start codon The first codon is AUG, which is the start codon and codes for Methionine (Met). ### Step 4: Identify the stop codon We need to look for stop codons in the sequence. The stop codons are UAA, UAG, and UGA. In our sequence, the first stop codon encountered is UAA. ### Step 5: Count the amino acids until the stop codon Now, we will count the number of codons from the start codon (AUG) up to, but not including, the stop codon (UAA): 1. AUG - Methionine (1) 2. CCC - Proline (2) 3. CAC - Histidine (3) 4. CAC - Histidine (4) 5. UUA - Leucine (5) 6. UAU - Tyrosine (6) 7. AUA - Isoleucine (7) The stop codon UAA is the eighth codon, which means we stop counting here. ### Step 6: Conclusion The total number of amino acids coded by the given mRNA sequence is **7**. ### Final Answer **7 amino acids will be coded by the given intron.** ---
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