The number of possible optical isomers f...

The number of possible optical isomers for complexes `MA_(2)B_(2)` with `sp^(3)` and `dsp^(2)` hybridized metal atoms, respectively, is :
Note A and B are unidentate neutral and unidentate monoanionic ligands, respectively.

A

2 and 2

B

0 and 0

C

0 and 2

D

0 and 1

Verified by Experts

The correct Answer is:

B

Similar Questions

Explore conceptually related problems

Total number of possible isomers of complex [Pd(NH_(3))_(2)(SCN)_(2)]

The possible number of the optical isomers in [Cr(en)_(2)CI_(2)]^(o+) is .

The number of possible isomers of an octahedral complex [Co(C_(2)O_(4))_(2)(NH_(3))_(2)]^- is

The maximum number of 180^(@) angle possible between X-M-X bond for compounds with sp^(3)d^(2) and sp^(3) d hybridisation respectively are

Number of possible isomer for the complex [Co(en)_(2)CI_(2)]CI will be: (em = ethylenediamine)

The possible number of structural and stereo isomers for the complex [MBr_(2)Cl_(2)]SO_(4) is

For the complex [Ma_2B_2] if M is sp^3 or dsp^2 hybridised respectively then total number of optical isomers are respectively:

How many geometrical isomers are possible for MA_(2)B_(2)C_(2) ?

How many sp^(2) and sp-hybridised carbon atoms are present respectively in the following compound ?