Home
Class 12
CHEMISTRY
The order of the oxidation state of the ...

The order of the oxidation state of the phos- phorus atom in `H_3PO_2, H_3PO_4 , H_3PO_3` and `H_4P_2O_6` is : -

A

`H_3PO_4 gt H_3PO_2 gt H_3PO_3 gt H_4P_2O_6`

B

`H_3PO_4 gt H_2P_2O_6 gt H_3PO_3 gt H_3PO_2`

C

`H_3PO_2 gt H_3PO_3 gt H_4P_2O_6 gt H_3PO_4`

D

`H_3PO_4 gt H_3PO_2 gt H_3PO_4 gt H_4P_2O_6`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the order of the oxidation state of the phosphorus atom in the compounds \( H_3PO_2 \), \( H_3PO_4 \), \( H_3PO_3 \), and \( H_4P_2O_6 \), we need to calculate the oxidation state of phosphorus in each compound step by step. ### Step 1: Calculate the oxidation state of phosphorus in \( H_3PO_2 \) 1. **Identify the oxidation states of other elements**: - Hydrogen (H) has an oxidation state of +1. - Oxygen (O) has an oxidation state of -2. 2. **Set up the equation**: \[ 3(+1) + x + 2(-2) = 0 \] where \( x \) is the oxidation state of phosphorus. 3. **Solve the equation**: \[ 3 + x - 4 = 0 \implies x - 1 = 0 \implies x = +1 \] ### Step 2: Calculate the oxidation state of phosphorus in \( H_3PO_4 \) 1. **Set up the equation**: \[ 3(+1) + x + 4(-2) = 0 \] 2. **Solve the equation**: \[ 3 + x - 8 = 0 \implies x - 5 = 0 \implies x = +5 \] ### Step 3: Calculate the oxidation state of phosphorus in \( H_3PO_3 \) 1. **Set up the equation**: \[ 3(+1) + x + 3(-2) = 0 \] 2. **Solve the equation**: \[ 3 + x - 6 = 0 \implies x - 3 = 0 \implies x = +3 \] ### Step 4: Calculate the oxidation state of phosphorus in \( H_4P_2O_6 \) 1. **Set up the equation**: \[ 4(+1) + 2x + 6(-2) = 0 \] 2. **Solve the equation**: \[ 4 + 2x - 12 = 0 \implies 2x - 8 = 0 \implies 2x = 8 \implies x = +4 \] ### Summary of Oxidation States - \( H_3PO_2 \): +1 - \( H_3PO_4 \): +5 - \( H_3PO_3 \): +3 - \( H_4P_2O_6 \): +4 ### Step 5: Arrange in order of oxidation states The order of the oxidation states of phosphorus in the compounds is: 1. \( H_3PO_4 \) (+5) 2. \( H_4P_2O_6 \) (+4) 3. \( H_3PO_3 \) (+3) 4. \( H_3PO_2 \) (+1) ### Final Answer The order of the oxidation state of phosphorus in \( H_3PO_2, H_3PO_4, H_3PO_3, \) and \( H_4P_2O_6 \) is: \[ H_3PO_4 > H_4P_2O_6 > H_3PO_3 > H_3PO_2 \]
Promotional Banner

Similar Questions

Explore conceptually related problems

What are the oxidation states of phosphorous in the following : H_(3)PO_(4)

The false statement of the acids of phosphorus H_3 PO_2, H_3 PO_3 and H_3 PO_4 is

What are the oxidation states of phosphorous in the following : H_(3)PO_(3) ​

What is the sum of the oxidation state of phosphorus and number of P-OH bonds in H_3PO_4 ?

The true statement of the acids of phosphorus H_(3)PO_(2),H_(3)PO_(3) and H__(3)PO_(4) is :

What is the oxidation number of phosphorus in H_(3)PO_(4) molecule ?

The true statement for the acids of phosphorus, H_(3)PO_(2), H_(3)PO_(3) and H_(3)PO_(4) is

What are the oxidation states of phosphorus in the following compounds ? H_(3)PO_(2),H_(3)PO_(4),Mg_(2)P_(2)O_(7),PH_(3),HPO_(3)

Basicity of H_3 PO_4 and H_3 PO_3 are

What are the oxidation states of phosphorus in the following: (i) H_(3)PO_(3) , (ii) PCl_(3) , (iii) Ca_(3)P_(2) (iv) Na_(3)PO_(4) , (v) POF_(3)