When `SO_2` gas is passed into aqueous `Na_2CO_3` , the product (s) formed is (are)

Options

A. `NaHSO_4`
B. `Na_2SO_2`
C. `NaHSO_3`
D. `Na_2SO_3 and NaHSO_3`

Answer

To solve the question of what products are formed when \( SO_2 \) gas is passed into an aqueous solution of \( Na_2CO_3 \), we can follow these steps:

### Step 1: Write the Reactants
The reactants in this reaction are sulfur dioxide gas (\( SO_2 \)) and sodium carbonate (\( Na_2CO_3 \)) in aqueous solution.

### Step 2: Identify the Reaction
When \( SO_2 \) is introduced to an aqueous solution of \( Na_2CO_3 \), it reacts with the carbonate ions (\( CO_3^{2-} \)) present in the solution. The reaction can be represented as follows:
\[ Na_2CO_3 (aq) + SO_2 (g) + H_2O (l) \rightarrow NaHSO_3 (aq) + NaHCO_3 (aq) \]

### Step 3: Balance the Reaction
To ensure the reaction is balanced, we can rewrite it:
\[ Na_2CO_3 + SO_2 + H_2O \rightarrow 2 NaHSO_3 + CO_2 \]
This indicates that one mole of sodium carbonate reacts with one mole of sulfur dioxide and one mole of water to produce two moles of sodium bisulfite (\( NaHSO_3 \)) and one mole of carbon dioxide (\( CO_2 \)).

### Step 4: Identify the Products
From the balanced reaction, we can identify the products formed:
- Sodium bisulfite (\( NaHSO_3 \))
- Carbon dioxide (\( CO_2 \))

### Conclusion
Thus, the products formed when \( SO_2 \) gas is passed into aqueous \( Na_2CO_3 \) are \( NaHSO_3 \) and \( CO_2 \).

### Final Answer
The products formed are \( NaHSO_3 \) and \( CO_2 \).

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