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In a potentiometer experiment if the vol...

In a potentiometer experiment if the voltage across resistance R and R + r are balanced at the length `l_1 and l_2` respectively the value of resistance r will be

A

`((l_1-l_2)/(l_2))R`

B

`((l_1-l_2)/(l_1))R`

C

`((l_2-l_1)/(l_1))R`

D

`((l_2-l_1)/(l_2))R`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the principles of a potentiometer and the relationships between voltage, resistance, and length. ### Step-by-Step Solution: 1. **Understanding the Potentiometer Principle**: In a potentiometer, the potential difference (voltage) across a length of wire is directly proportional to the length of the wire. This can be expressed as: \[ V = k \cdot L \] where \( V \) is the voltage, \( k \) is a constant (proportionality constant), and \( L \) is the length of the wire. 2. **Setting Up the Equations**: For the first balance at length \( l_1 \) with resistance \( R \): \[ V = k \cdot l_1 \quad \text{(1)} \] For the second balance at length \( l_2 \) with resistance \( R + r \): \[ V' = k \cdot l_2 \quad \text{(2)} \] 3. **Relating Voltage to Resistance**: According to Ohm's law, the voltage across a resistor can also be expressed as: \[ V = I \cdot R \quad \text{and} \quad V' = I' \cdot (R + r) \] where \( I \) and \( I' \) are the currents through the resistors \( R \) and \( R + r \), respectively. 4. **Equating the Two Voltages**: Since both equations (1) and (2) represent the same potential difference, we can equate them: \[ k \cdot l_1 = I \cdot R \quad \text{and} \quad k \cdot l_2 = I' \cdot (R + r) \] 5. **Finding the Wavelength**: From the first equation, we can express \( k \): \[ k = \frac{V}{l_1} = \frac{I \cdot R}{l_1} \] Substituting \( k \) in the second equation: \[ \frac{I \cdot R}{l_1} \cdot l_2 = I' \cdot (R + r) \] 6. **Subtracting the Equations**: Rearranging gives: \[ I \cdot R \cdot \frac{l_2}{l_1} = I' \cdot (R + r) \] By subtracting the first equation from the second, we can isolate \( r \): \[ (R + r) - R = \frac{I \cdot R}{l_1} \cdot (l_2 - l_1) \] Thus, \[ r = \frac{I \cdot R}{l_1} \cdot (l_2 - l_1) \] 7. **Final Expression for Resistance \( r \)**: We can express \( r \) in terms of \( R \), \( l_1 \), and \( l_2 \): \[ r = \frac{R}{l_1} \cdot (l_2 - l_1) \] ### Conclusion: The value of resistance \( r \) can be expressed as: \[ r = R \cdot \frac{(l_2 - l_1)}{l_1} \]
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