The current gain for a transistor used in common - emitter configuration is 98. If the load resistance be `1 M Omega` and the internal resistance be `600Omega` , what is the voltage gain ?

Options

A. 90
B. 95
C. 100
D. none

Answer

To find the voltage gain of a transistor in a common-emitter configuration, we can use the formula:

\[ \text{Voltage Gain (A_v)} = \text{Current Gain (β)} \times \frac{R_L}{R_{in}} \]

where:
- \( \text{Current Gain (β)} = 98 \)
- \( R_L = 1 \, M\Omega = 10^6 \, \Omega \)
- \( R_{in} = 600 \, \Omega \)

### Step 1: Substitute the values into the formula

Substituting the given values into the voltage gain formula:

\[ A_v = 98 \times \frac{10^6}{600} \]

### Step 2: Calculate the fraction

First, calculate the fraction \( \frac{10^6}{600} \):

\[ \frac{10^6}{600} = \frac{10^6 \div 600}{1} = \frac{1000000}{600} \approx 1666.67 \]

### Step 3: Multiply by the current gain

Now, multiply this result by the current gain (98):

\[ A_v = 98 \times 1666.67 \approx 163333.33 \]

### Step 4: Approximate the final result

For practical purposes, we can round this to:

\[ A_v \approx 163333 \]

Thus, the voltage gain of the transistor in the common-emitter configuration is approximately 163333.

### Final Answer
The voltage gain is approximately **163333**.

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