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Suppose the reaction PC1(5(s))hArrPC1(3(...

Suppose the reaction `PC1_(5(s))hArrPC1_(3(s)) + C1_(2(g))` is in a closed vessel at equilibrium stage. What is the effect on equilibrium concentration of `C1_(2(g))` by adding `PCl_(5)` at constant temperature ?

A

Unaffected

B

Increases

C

Decreases

D

Cannot be described without the value of `K_p`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the effect on the equilibrium concentration of \( Cl_2(g) \) when \( PCl_5(s) \) is added at constant temperature, we can follow these steps: ### Step 1: Understand the Reaction The equilibrium reaction given is: \[ PCl_5(s) \rightleftharpoons PCl_3(s) + Cl_2(g) \] ### Step 2: Identify the Components - \( PCl_5 \) is a solid and does not affect the equilibrium concentration in terms of pressure or concentration since solids do not appear in the equilibrium expression. - \( PCl_3 \) is also a solid and similarly does not affect the equilibrium. - \( Cl_2 \) is a gas and its concentration will be affected by changes in the equilibrium. ### Step 3: Apply Le Chatelier's Principle According to Le Chatelier's Principle, if a system at equilibrium is disturbed, the system will adjust to counteract the disturbance and restore a new equilibrium. ### Step 4: Analyze the Effect of Adding \( PCl_5 \) When \( PCl_5 \) is added to the system: - The concentration of \( PCl_5 \) increases. - Since \( PCl_5 \) is a solid, its addition does not change the concentration in terms of the equilibrium expression. - However, the system will respond by shifting the equilibrium to the right to consume some of the \( PCl_5 \) and produce more \( Cl_2 \). ### Step 5: Conclusion on \( Cl_2(g) \) Concentration As a result of the shift to the right, the concentration of \( Cl_2(g) \) will increase. ### Final Answer The equilibrium concentration of \( Cl_2(g) \) will **increase** upon adding \( PCl_5 \) at constant temperature. ---
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