Home
Class 12
CHEMISTRY
For solution of weak electrolytic, the d...

For solution of weak electrolytic, the degree of ionization

A

Will be reciprocal to the dilution

B

Will be proportional to dilution

C

Will be proportional to the square root of dilution

D

Will be proportional to concentration of electrolyte

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the degree of ionization for a solution of a weak electrolyte, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Weak Electrolytes**: - A weak electrolyte is a substance that partially ionizes in solution. This means that not all of the solute dissociates into ions. 2. **Ostwald's Dilution Law**: - Ostwald's dilution law relates the degree of ionization (α) of a weak electrolyte to its concentration (C) and its dissociation constant (K). It states that as the dilution of the solution increases, the degree of ionization also increases. 3. **Dissociation of a Binary Electrolyte**: - Consider a binary electrolyte AB that dissociates into A⁺ and B⁻ ions: \[ AB \rightleftharpoons A^+ + B^- \] 4. **Expression for the Dissociation Constant (K)**: - The dissociation constant (K) for the reaction can be expressed as: \[ K = \frac{[A^+][B^-]}{[AB]} \] 5. **Setting Up Initial and Equilibrium Concentrations**: - Let the initial concentration of AB be C. At equilibrium: - The concentration of A⁺ and B⁻ will be αC (where α is the degree of ionization). - The concentration of AB will be \(C(1 - \alpha)\). 6. **Substituting into the Dissociation Constant Expression**: - Substitute the equilibrium concentrations into the expression for K: \[ K = \frac{(\alpha C)(\alpha C)}{C(1 - \alpha)} = \frac{\alpha^2 C^2}{C(1 - \alpha)} \] 7. **Simplifying the Expression**: - Since α is very small for weak electrolytes, we can approximate \(1 - \alpha \approx 1\): \[ K \approx \frac{\alpha^2 C}{1} \] - Rearranging gives: \[ \alpha^2 = \frac{K}{C} \] 8. **Finding the Degree of Ionization (α)**: - Taking the square root of both sides, we find: \[ \alpha = \sqrt{\frac{K}{C}} \] 9. **Conclusion**: - This shows that the degree of ionization (α) is proportional to the square root of the dilution (or concentration) of the electrolyte. Therefore, the correct answer is that the degree of ionization is proportional to the square root of dilution. ### Final Answer: The degree of ionization (α) of a weak electrolyte is proportional to the square root of its dilution.
Promotional Banner

Similar Questions

Explore conceptually related problems

A: Molar conductivity of solution increase with dilution for weak electrolyte. R: Degree of ionization increases with dilution.

In a 0.2 molal aqueous solution of a weak acid HX the degree of ionization is 0.3 . Taking k_(f) for water as 1.85 the freezing point of the solution will be nearest to-

What should be the concentration of a weak electrolyte AB, When its degree of ionisation is increased twice.

For the weak electrolyte , their degree of dissociation increase

Assertion(A) Lambda_(m) for weak electrolytes shows a sharp increase when the electrolytic solution is diluted. Reason(R) For weak electrolytes degree of dissociation increases with dilution of solution. (a) Both assertion and reason are true and the reason is the correct explanation of assertion. (b) Both assertion and reason are true and reason is not the correct explanation of assertion. (c) Assertion is true but the reason is false. (d) Both assertion and reason are false.

What happens to conductance of solution of a weak electrolyte , when heated

The ionization constant of phenol is 1.0xx10^(-10) . What is the concentration of phenolate ion in 0.05 M solution of phenol? What will be its degree of ionization if the solution is also 0.01 M in sodium phenolate?

A 0.20 M solution of methanoic acid has degree of ionization of 0.032. Its dissociation constant would be

On diluting aqueous solution of weak electrolyte to 100 times

If alpha is the degree of ionization, C the concentration of a weak electrolyte and K_(a) the acid ionization constant , then the correct relationship between alpha and C is