Find the end product in the given sequence of reaction `HC-=CHoverset(1%HgSO_4)rarrAoverset(CH_3MgX)rarrBoverset([O])rarr`

Options

A. Ethanol
B. Acetic acid
C. Acetone
D. Isopropyl alcohol

Answer

To solve the given sequence of reactions, we will break down each step systematically.

### Step 1: Reaction of Ethyne with 1% HgSO4
The starting compound is ethyne (HC≡CH). When ethyne reacts with dilute sulfuric acid (1% HgSO4), it undergoes hydration to form an aldehyde. The reaction can be represented as follows:

\[ \text{HC≡CH} + \text{H}_2\text{SO}_4 \xrightarrow{1\% \text{HgSO}_4} \text{CH}_3\text{CHO} \]

**Product A:** The product formed is acetaldehyde (CH3CHO).

### Step 2: Reaction of Acetaldehyde with Grignard Reagent
Next, we take the product A (acetaldehyde) and react it with a Grignard reagent, which is represented as CH3MgX. The Grignard reagent will attack the carbonyl carbon of the aldehyde, leading to the formation of an alcohol after hydrolysis.

The reaction can be represented as:

\[ \text{CH}_3\text{CHO} + \text{CH}_3\text{MgX} \xrightarrow{\text{H}_2\text{O}} \text{CH}_3\text{CHOHCH}_3 \]

**Product B:** The product formed is 2-butanol (CH3CHOHCH3).

### Step 3: Oxidation of 2-Butanol
Finally, we take product B (2-butanol) and oxidize it. The oxidation of a secondary alcohol typically leads to the formation of a ketone.

The reaction can be represented as:

\[ \text{CH}_3\text{CHOHCH}_3 \xrightarrow{[O]} \text{CH}_3\text{COCH}_3 \]

**Final Product:** The final product formed is acetone (CH3COCH3).

### Conclusion
The end product of the given sequence of reactions is acetone (CH3COCH3).

### Summary of Steps:
1. Ethyne reacts with dilute HgSO4 to form acetaldehyde (CH3CHO).
2. Acetaldehyde reacts with CH3MgX to form 2-butanol (CH3CHOHCH3).
3. 2-butanol is oxidized to form acetone (CH3COCH3).