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The angular speed of second hand in a wa...

The angular speed of second hand in a watch is

A

`pi/(1800)rads^(-1)`

B

`pi/(30)rads^(-1)`

C

`pi/(90)rads^(-1)`

D

`pi/(60)rads^(-1)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the angular speed of the second hand in a watch, we can follow these steps: ### Step 1: Understand the movement of the second hand The second hand of a watch completes one full revolution in 60 seconds. A full revolution corresponds to an angle of \(2\pi\) radians. ### Step 2: Calculate the angular speed Angular speed (\(\omega\)) is defined as the angle rotated per unit time. The formula for angular speed is: \[ \omega = \frac{\text{Angle rotated}}{\text{Time taken}} \] ### Step 3: Substitute the values In this case, the angle rotated is \(2\pi\) radians and the time taken is 60 seconds. Therefore, we can substitute these values into the formula: \[ \omega = \frac{2\pi \text{ radians}}{60 \text{ seconds}} \] ### Step 4: Simplify the expression Now, we simplify the fraction: \[ \omega = \frac{2\pi}{60} = \frac{\pi}{30} \text{ radians per second} \] ### Conclusion Thus, the angular speed of the second hand in a watch is \(\frac{\pi}{30}\) radians per second. ---
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