Home
Class 12
CHEMISTRY
The relative abundance of two isotopes o...

The relative abundance of two isotopes of an element with atomic weight 85 and 87 is 75% and 25% respectively. Then calculate the average atomic weight of element

A

`86.0`

B

`85.5`

C

`75.5`

D

`40.0`

Text Solution

AI Generated Solution

The correct Answer is:
To calculate the average atomic weight of the element based on the relative abundance of its isotopes, we can follow these steps: ### Step 1: Identify the isotopes and their atomic weights We have two isotopes: - Isotope 1 (M1) with an atomic weight of 85 - Isotope 2 (M2) with an atomic weight of 87 ### Step 2: Identify the relative abundances The relative abundances are given as: - Isotope 1 (x1) = 75% = 0.75 - Isotope 2 (x2) = 25% = 0.25 ### Step 3: Use the formula for average atomic weight The formula to calculate the average atomic weight (A_avg) is: \[ A_{avg} = \frac{(M_1 \cdot x_1) + (M_2 \cdot x_2)}{x_1 + x_2} \] ### Step 4: Substitute the values into the formula Substituting the values we have: \[ A_{avg} = \frac{(85 \cdot 0.75) + (87 \cdot 0.25)}{0.75 + 0.25} \] ### Step 5: Calculate the numerator Calculating the products: - \(85 \cdot 0.75 = 63.75\) - \(87 \cdot 0.25 = 21.75\) Now, add these two results: \[ 63.75 + 21.75 = 85.5 \] ### Step 6: Calculate the denominator The denominator is: \[ 0.75 + 0.25 = 1 \] ### Step 7: Final calculation Now, substitute back into the formula: \[ A_{avg} = \frac{85.5}{1} = 85.5 \] ### Conclusion The average atomic weight of the element is **85.5**. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

The mass number of three isotopes of an element are 11,12 and 13 .Their percentage ohandances 80,15 and 5 , respectively .What is the atomic weight of the element ?

The mass numbers of three istopes of an element are 10,12 and 14 units .Their precentage abundance is 80,15 and 5 respectively .What is the atomic weight of the element ?

The relative abundance of three isotopes of carbon C^(12), C^(13) and C^14 are 98.892%, 1.108% and 2 xx 10^(-10) % respectively. If the relative atomic masses of these isotopes are 12.00, 13.00335 and 14.00317 amu respectively, find the average atomic mass of carbon.

Approximate atomic weight of an element is 26.89 . If its equivalent weight is 8.9 , the exact atomic weight of element would be

Calculate the weight of : 10 atoms of sodium.

There are two isotopes of an element with atomic mass z. Heavier one has atomic mass z+2 and lighter one has z-1, then abundance of lighter one is

(i) How would you define the terms atomic mass and molecular mass ? (ii) Nitrogen occurs in nature in the form of two isotopes with atomic masses 14 and 15 respectively. If the average atomic mass of nitrogen is 14.0067, what is the percent abundance of the two isotopes ?

An element exist in nature in two isotopic forms: X^(30)(90%) and X^(32)(10%) . What is the average atomic mass of element?

(a) Two stable isotope of ._3Li^6 and ._3Li^7 have respective abundances of 7.5% and 92.5% . These isotopes have masses 6.01512 and 7.01600 u respectively. Find the atomic weight of lithium. (b) Boron has two stable isotopes ._5B^(10) and ._5B^(11) . Their respective masses are 10.01294 u and 11.00931 u, and the atomic weight of boron is 10.81 u. Find the abundances of ._5B^(10) and ._5B^(11) .

(a) Two stable isotope of ._3Li^6 and ._3Li^7 have respective abundances of 7.5% and 92.5% . These isotopes have masses 6.01512 and 7.01600 u respectively. Find the atomic weight of lithium. (b) Boron has two stable isotopes ._5B^(10) and ._5B^(11) . Their respective masses are 10.01294 u and 11.00931 u, and the atomic weight of boron is 10.81 u. Find the abundances of ._5B^(10) and ._5B^(11) .