Which one of the following is reduced with zinc and hydrochloric acid to give the corresponding hydrocarbon?

Options

A. Ethyl acetate
B. Acetic acid
C. Acetamide
D. Butan - 2 - one

Answer

To solve the question, we need to identify which compound can be reduced to a hydrocarbon using zinc and hydrochloric acid. This reduction is typically associated with the Clemensen reduction, which is used to convert ketones or aldehydes into alkanes.

### Step-by-Step Solution:

1. **Understand the Clemensen Reduction**:
- The Clemensen reduction is a chemical reaction that reduces ketones or aldehydes to alkanes using zinc amalgam and hydrochloric acid.
- The general reaction can be represented as:
\[ \text{R}_2\text{C=O} + \text{Zn/HCl} \rightarrow \text{R}_2\text{CH}_2 + \text{H}_2\text{O} \]
- Here, R represents alkyl groups.

2. **Identify the Options**:
- We need to analyze the given options to see which one is a ketone or aldehyde that can undergo this reduction.

3. **Check Each Option**:
- If we have the option butan-2-one (which is a ketone), we can apply the Clemensen reduction:
\[ \text{CH}_3\text{CH}_2\text{COCH}_3 + \text{Zn/HCl} \rightarrow \text{CH}_3\text{CH}_2\text{CH}_3 + \text{H}_2\text{O} \]
- This reaction shows that butan-2-one is reduced to butane.

4. **Conclusion**:
- Among the options provided, butan-2-one is the only compound that is a ketone and can be reduced to the corresponding hydrocarbon (butane) using zinc and hydrochloric acid.

### Final Answer:
- The correct answer is **butan-2-one**.