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Based on data given below for the electr...

Based on data given below for the electrode potential , reducing power of `Fe^(2+)` , Al and `Br^(-)` will increase in the order
`Br_(2)(aq)+2e^(-)rarr2Br^(-)(aq),E^@=+1.08V`
`Al^(3+)(aq)+3e^(-)rarrAl(s),E^@=-1.66V`
`Fe^(3+)(aq)+e^(-2)rarrFe^(+2) (aq) , E^(@) =+0.77V`

A

`Br^(-) lt Fe^(2+) lt Al`

B

`Al lt Br^(-) lt Fe^(2+)`

C

`Fe^(2+) lt Al lt Br^(-)`

D

`Al lt Fe ^(2+) lt Br ^(-)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the increasing order of reducing power of \( Fe^{2+} \), \( Al \), and \( Br^{-} \), we will analyze the given standard electrode potentials and derive the order based on their reducing abilities. ### Step-by-Step Solution: 1. **Identify the Given Electrode Potentials:** - For \( Br_2 + 2e^- \rightarrow 2Br^- \), \( E^\circ = +1.08 \, V \) - For \( Al^{3+} + 3e^- \rightarrow Al \), \( E^\circ = -1.66 \, V \) - For \( Fe^{3+} + e^- \rightarrow Fe^{2+} \), \( E^\circ = +0.77 \, V \) 2. **Understand the Relationship Between Electrode Potential and Reducing Power:** - The standard electrode potential (\( E^\circ \)) indicates the tendency of a species to gain electrons (be reduced). A higher \( E^\circ \) value means a stronger oxidizing agent and thus a weaker reducing agent. - Conversely, a lower \( E^\circ \) value indicates a stronger reducing agent. 3. **Rank the Electrode Potentials:** - From the values: - \( Br^{-} \) has the highest \( E^\circ \) (+1.08 V) - \( Fe^{2+} \) has an intermediate \( E^\circ \) (+0.77 V) - \( Al \) has the lowest \( E^\circ \) (-1.66 V) 4. **Determine the Order of Reducing Power:** - Since reducing power is inversely related to the standard electrode potential: - \( Al \) (lowest potential, strongest reducing agent) - \( Fe^{2+} \) (intermediate potential) - \( Br^{-} \) (highest potential, weakest reducing agent) 5. **Final Order of Increasing Reducing Power:** - Therefore, the order of increasing reducing power is: \[ Br^{-} < Fe^{2+} < Al \] ### Conclusion: The reducing power of \( Fe^{2+} \), \( Al \), and \( Br^{-} \) will increase in the order: \[ Br^{-} < Fe^{2+} < Al \]
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