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A photon of energy 15eV collides with H-...

A photon of energy `15eV` collides with `H-`atom. Due to this collision, `H-`atom gets ionized. The maximum kinetic energy of emitted elecrtron is:

A

1.4 eV

B

5 eV

C

15 eV

D

13.6 eV

Text Solution

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The correct Answer is:
To find the maximum kinetic energy of the emitted electron when a photon of energy 15 eV collides with an H- atom, we can follow these steps: ### Step 1: Identify the energy of the photon The energy of the incoming photon is given as: \[ E_{\text{photon}} = 15 \, \text{eV} \] ### Step 2: Determine the ionization energy of the H- atom The ionization energy required to ionize an H- atom is known to be: \[ E_{\text{ionization}} = 13.6 \, \text{eV} \] ### Step 3: Calculate the maximum kinetic energy of the emitted electron The maximum kinetic energy (KE_max) of the emitted electron can be calculated using the formula: \[ KE_{\text{max}} = E_{\text{photon}} - E_{\text{ionization}} \] Substituting the values we have: \[ KE_{\text{max}} = 15 \, \text{eV} - 13.6 \, \text{eV} \] ### Step 4: Perform the subtraction Now, we perform the subtraction: \[ KE_{\text{max}} = 15 \, \text{eV} - 13.6 \, \text{eV} = 1.4 \, \text{eV} \] ### Conclusion Thus, the maximum kinetic energy of the emitted electron is: \[ KE_{\text{max}} = 1.4 \, \text{eV} \] ### Final Answer The maximum kinetic energy of the emitted electron is **1.4 eV**. ---
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