`BF_3` on reaction with sodium hydride produces

Options

A. `B_2F_6`
B. `B_2H_(10)`
C. `B_2F_(6)`
D. `B_2H_(6)`

Answer

To solve the question regarding the reaction of BF₃ (boron trifluoride) with sodium hydride (NaH), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are BF₃ (boron trifluoride) and NaH (sodium hydride).

2. **Understand the Role of Sodium Hydride**:
- Sodium hydride (NaH) provides hydride ions (H⁻) which can react with BF₃. The hydride ion is a strong nucleophile and can react with electron-deficient species like BF₃.

3. **Predict the Products**:
- When BF₃ reacts with NaH, it is known to form diborane (B₂H₆) and sodium fluoride (NaF) as a byproduct. The overall reaction can be summarized as:
\[ 6 \, \text{NaH} + 2 \, \text{BF}_3 \rightarrow \text{B}_2\text{H}_6 + 6 \, \text{NaF} \]

4. **Balancing the Reaction**:
- To ensure that the reaction is balanced, we need to check the number of atoms on both sides:
- **Left Side**: 2 Boron (B), 6 Fluorine (F), and 6 Hydrogen (H) from NaH.
- **Right Side**: 2 Boron (B) from B₂H₆, 6 Fluorine (F) from NaF, and 6 Hydrogen (H) from B₂H₆.
- The equation is balanced as both sides have the same number of each type of atom.

5. **Conclusion**:
- The main product of the reaction between BF₃ and NaH is diborane (B₂H₆), and the side product is sodium fluoride (NaF).

### Final Answer:
The product formed when BF₃ reacts with sodium hydride is diborane (B₂H₆).