Home
Class 12
CHEMISTRY
End product D of reaction sequence is CH...

End product D of reaction sequence is `CH_3Broverset(KCN)rarrAoverset(H_2"O"//H^+)rarrBoverset(SOCl_2)rarrCoverset((C_2H_5)_2Cd)rarrD`

A

`CH_3CH_2-O-C_2H_5`

B

`C_2H_5COOCH_3`

C

`CH_3COC_2H_5`

D

`CH_3COOC_2H_5`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the end product D of the reaction sequence starting from CH3Br, we will break down each step of the reaction sequence systematically. ### Step 1: Reaction of CH3Br with KCN - **Reaction**: CH3Br + KCN → CH3CN (Acetonitrile) - **Explanation**: Methyl bromide (CH3Br) reacts with potassium cyanide (KCN). The nucleophilic cyanide ion (CN-) attacks the electrophilic carbon in CH3Br, leading to the formation of acetonitrile (CH3CN) and the elimination of KBr. ### Step 2: Hydrolysis of Acetonitrile - **Reaction**: CH3CN + H2O/H+ → CH3COOH (Acetic Acid) - **Explanation**: Acetonitrile undergoes hydrolysis in the presence of water and an acid catalyst (H+) to form acetic acid (CH3COOH). The cyano group (-CN) is converted into a carboxylic acid (-COOH) during this process. ### Step 3: Reaction of Acetic Acid with Thionyl Chloride (SOCl2) - **Reaction**: CH3COOH + SOCl2 → CH3COCl (Acetyl Chloride) - **Explanation**: Acetic acid reacts with thionyl chloride to produce acetyl chloride (CH3COCl). This reaction involves the conversion of the -OH group in acetic acid to a -Cl group, resulting in the formation of an acid chloride. ### Step 4: Reaction of Acetyl Chloride with Diethyl Cadmium - **Reaction**: CH3COCl + (C2H5)2Cd → CH3C(O)(C2H5)Cl - **Explanation**: Diethyl cadmium ((C2H5)2Cd) acts as a nucleophile and attacks the carbonyl carbon in acetyl chloride. This results in the formation of a tetrahedral intermediate, which then collapses, leading to the elimination of chloride ion (Cl-) and the formation of the final product. ### Step 5: Final Product Formation - **Final Product**: CH3C(O)C2H5 - **Explanation**: After the elimination of Cl-, the final product formed is methyl ethyl ketone (also known as 3-pentanone), which has the structure CH3C(O)C2H5. ### Conclusion The end product D of the reaction sequence is methyl ethyl ketone, represented as CH3COC2H5. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

End product S of the reaction sequence is CH_3-CH_2Broverset(KCN)(rarr)P overset(H_2O //H^+)(rarr)Q overset(SOCl_2)(rarr) R overset((C_2H_5)_(2)Cd)(rarr)S

The product C of the reaction CH_(3)Cloverset(KCN)toAoverset(H_(2)O //H^(+))toBoverset(NH_(3))to C is

In the following sequence of reaction, the product C is CH_(3)-Br overset(KCN) rarr A overset(H_(2)O^(+))rarr B overset(LiAlH_(4))underset("Ether")rarr C

In the given reaction sequence C_6H_5-COOHoverset(SOCl_2)rarr(A)overset(NH_2OH)rarr(B)overset(NaOH//Delta)rarr(C), 'C' will be

In the reaction sequence CH_3-CH_2-CH_2-Broverset(AgCN) rarr (X) overset (H_2O/ H^(+))rarr(Y) (Y) will be

The end product (C) of the following reaction is : CH_(3)COOH overset(CaCO_(3))rarrAoverset("Heat")rarrBoverset(NH_(2)OH)rarr

In the reaction sequence C_6H_5CHOoverset(NaCN//HCl)rarr(X)overset(H_2"O"//H^o+)rarr product, Product will be

In the following sequence of reactions: CH_(3)CH_(2)CH_(2)OHoverset(P+I_(2))rarrAoverset(Mg)underset("dry ether")rarrBoverset(HCHO)rarrCoverset(H_(2)O)rarrD the compound D is:

The end product (B) in the following sequence of reactions is CH_(3)Cl overset(KCN)rarr A overset(H_(2)O //H^(+))rarr B

Find the end product in the given sequence of reaction HC-=CHoverset(1%HgSO_4)rarrAoverset(CH_3MgX)rarrBoverset([O])rarr