`Be_2C+4H_2Orarr2X+CH_4`
`X+2HClrarrY`
'X' and 'Y' formed in the above two reactions are -

Options

A. `BeCO_3 and Be(OH)_2` , respectively
B. `Be(OH)_2and BeCl_2` respectively
C. `Be(OH)_2and [Be(OH)_4]Cl_2` respectively
D. `[Be(OH)_4]^(2) and BeCl_2` , respectively

Answer

To solve the problem, we need to analyze the reactions given in the question step by step.

### Step 1: Identify the Reaction of Beryllium Carbide with Water
The first reaction involves beryllium carbide (Be₂C) reacting with water (H₂O). The balanced reaction is:

\[ \text{Be}_2\text{C} + 4\text{H}_2\text{O} \rightarrow 2\text{Be(OH)}_2 + \text{CH}_4 \]

In this reaction, beryllium carbide reacts with water to produce beryllium hydroxide (Be(OH)₂) and methane (CH₄).

### Step 2: Identify the Product 'X'
From the first reaction, we can identify 'X' as beryllium hydroxide (Be(OH)₂).

### Step 3: Identify the Reaction of 'X' with Hydrochloric Acid
Next, we consider the second reaction where 'X' (which we identified as beryllium hydroxide) reacts with hydrochloric acid (HCl):

\[ \text{Be(OH)}_2 + 2\text{HCl} \rightarrow \text{BeCl}_2 + 2\text{H}_2\text{O} \]

In this reaction, beryllium hydroxide reacts with hydrochloric acid to produce beryllium chloride (BeCl₂) and water (H₂O).

### Step 4: Identify the Product 'Y'
From the second reaction, we can identify 'Y' as beryllium chloride (BeCl₂).

### Conclusion
Thus, the compounds 'X' and 'Y' formed in the reactions are:
- **X**: Beryllium hydroxide (Be(OH)₂)
- **Y**: Beryllium chloride (BeCl₂)

### Final Answer
- **X**: Beryllium hydroxide (Be(OH)₂)
- **Y**: Beryllium chloride (BeCl₂)

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