In the series of reaction X and Y are respectively are `C_6H_5NH_2overset(NaNO_2//HCl)rarrXoverset(HNO_2)rarrY+N_2+HCl`

Options

A. `C_6H_5-N=N-C_6H_5,C_6H_5N_2^o+Cl^(Theta)`
B. `C_6H_5N_2^o+Cl^(Theta),C_6H_5-N=N-C_6H_5,`
C. `C_6H_5N_2^o+Cl^(Theta),C_6H_5NO_2`
D. `C_6H_5NO_2,C_6H_6`

Answer

To solve the question regarding the series of reactions involving aniline, we can break down the steps as follows:

### Step-by-Step Solution:

1. **Identify the Starting Material:**
The starting material is aniline, which has the chemical formula \( C_6H_5NH_2 \).

2. **First Reaction: Diazotization:**
Aniline reacts with sodium nitrite (\( NaNO_2 \)) in the presence of hydrochloric acid (\( HCl \)) at low temperatures (around 0°C). This reaction is known as diazotization and produces benzene diazonium chloride (\( C_6H_5N_2^+Cl^- \)).
\[ C_6H_5NH_2 + NaNO_2 + HCl \rightarrow C_6H_5N_2^+Cl^- + 2H_2O \]
**Product X:** Benzene diazonium chloride (\( C_6H_5N_2^+Cl^- \))

3. **Second Reaction: Formation of Nitrobenzene:**
The benzene diazonium chloride then reacts with nitrous acid (\( HNO_2 \)). In this reaction, the diazonium salt can be converted into nitrobenzene (\( C_6H_5NO_2 \)), releasing nitrogen gas (\( N_2 \)) and hydrochloric acid (\( HCl \)).
\[ C_6H_5N_2^+Cl^- + HNO_2 \rightarrow C_6H_5NO_2 + N_2 + HCl \]
**Product Y:** Nitrobenzene (\( C_6H_5NO_2 \))

4. **Final Products:**
After both reactions, the final products are:
- Product X: Benzene diazonium chloride (\( C_6H_5N_2^+Cl^- \))
- Product Y: Nitrobenzene (\( C_6H_5NO_2 \))

### Conclusion:
The correct identification of products X and Y from the reactions is:
- X = Benzene diazonium chloride (\( C_6H_5N_2^+Cl^- \))
- Y = Nitrobenzene (\( C_6H_5NO_2 \))