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How many alpha and beta-particles are em...

How many `alpha` and `beta`-particles are emitted in the transformation `""_(92)^(238)U rarr ""_(92)^(234)U`

A

`2alpha and 2beta`

B

`1alpha and 2beta`

C

`1 alpha` only

D

`2beta and 2alpha`

Text Solution

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The correct Answer is:
To solve the problem of how many alpha and beta particles are emitted in the transformation of Uranium-238 (U-238) to Uranium-234 (U-234), we can follow these steps: ### Step 1: Understand the transformation We start with Uranium-238, which has an atomic number (Z) of 92 and a mass number (A) of 238. The transformation we are looking at is: \[ _{92}^{238}U \rightarrow _{92}^{234}U \] ### Step 2: Determine the change in mass number and atomic number In this transformation: - The mass number decreases from 238 to 234, indicating a decrease of 4. - The atomic number remains the same at 92. ### Step 3: Identify the emission of alpha particles An alpha particle (α) has a mass number of 4 and an atomic number of 2. When an alpha particle is emitted: - The mass number decreases by 4. - The atomic number decreases by 2. ### Step 4: Calculate the number of alpha particles emitted To decrease the mass number from 238 to 234, we can see that: - Emitting 1 alpha particle will decrease the mass number by 4 (from 238 to 234). - The atomic number will decrease from 92 to 90. Thus, after emitting 1 alpha particle: \[ _{90}^{234}Th \] (Thorium-234) ### Step 5: Identify the need for beta particles Now, we have Thorium-234 (Th-234) with an atomic number of 90. To convert this back to Uranium (U), we need to increase the atomic number back to 92: - We can achieve this by emitting beta particles (β). ### Step 6: Calculate the number of beta particles emitted A beta minus particle (β-) has no mass and increases the atomic number by 1. To go from atomic number 90 (Th) to 92 (U), we need to emit 2 beta particles: 1. After 1 beta emission: \[ _{91}^{234}Pa \] (Protactinium-234) 2. After another beta emission: \[ _{92}^{234}U \] (Uranium-234) ### Conclusion In total, we have: - 1 alpha particle emitted - 2 beta particles emitted Thus, the answer to the question is: **1 alpha particle and 2 beta particles.**
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