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A girl of mass 50 kg stands on a railro...

A girl of mass 50 kg stands on a railroad car of mass 75 kg moving with velocity `20 ms^(-1)` . Now , the girl begins to run with a velocity of `10ms^(-1)` with respect to the car in the same direction , as that of the car. The velocity of the car at this instant will be

A

`20 ms ^(-1)`

B

`24 ms ^(-1)`

C

`16ms ^(-1)`

D

`18 ms ^(-1)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will use the principle of conservation of momentum. Here are the steps to find the final velocity of the railroad car after the girl starts running. ### Step-by-Step Solution: 1. **Identify the Initial Conditions:** - Mass of the girl (m_g) = 50 kg - Mass of the car (m_c) = 75 kg - Initial velocity of the car (V_initial) = 20 m/s - Velocity of the girl with respect to the car (V_g/c) = 10 m/s (in the same direction as the car) 2. **Calculate the Initial Momentum:** The total initial momentum (P_initial) of the system (girl + car) can be calculated as: \[ P_{\text{initial}} = (m_g + m_c) \times V_{\text{initial}} = (50 \, \text{kg} + 75 \, \text{kg}) \times 20 \, \text{m/s = 125 \, kg} \times 20 \, \text{m/s} = 2500 \, \text{kg m/s} \] 3. **Determine the Final Velocities:** Let the final velocity of the car be \( V_f \). The velocity of the girl with respect to the ground (V_g) can be expressed as: \[ V_g = V_f + V_g/c = V_f + 10 \, \text{m/s} \] 4. **Calculate the Final Momentum:** The total final momentum (P_final) of the system can be expressed as: \[ P_{\text{final}} = m_c \times V_f + m_g \times V_g = 75 \, \text{kg} \times V_f + 50 \, \text{kg} \times (V_f + 10 \, \text{m/s}) \] Simplifying this gives: \[ P_{\text{final}} = 75 V_f + 50 V_f + 500 = 125 V_f + 500 \] 5. **Set Initial Momentum Equal to Final Momentum:** According to the conservation of momentum: \[ P_{\text{initial}} = P_{\text{final}} \] Therefore, we have: \[ 2500 = 125 V_f + 500 \] 6. **Solve for \( V_f \):** Rearranging the equation: \[ 125 V_f = 2500 - 500 \] \[ 125 V_f = 2000 \] \[ V_f = \frac{2000}{125} = 16 \, \text{m/s} \] ### Final Answer: The final velocity of the car is \( V_f = 16 \, \text{m/s} \).
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