In the `beta^+` decay process , the following changes take place inside the nucleus

Options

A. `._Z^AXrarr._(Z-1)^AY+e^(+)+gamma`
B. `._Z^AXrarr._(Z+1)^AY+e^(-)+bargamma`
C. `._Z^AXrarr._(Z)^AY+e^(-)+gamma`
D. `._Z^AXrarr._(Z)^AY+e^(-)+bargamma`

Answer

To solve the question regarding the changes that take place during the beta plus (β+) decay process, we can break it down into a series of steps:

### Step-by-Step Solution:

1. **Understanding Beta Plus Decay**:
In beta plus decay, a proton in the nucleus is converted into a neutron. This process involves the emission of a positron (the antiparticle of an electron) and a neutrino.

2. **Change in Atomic Number**:
- The atomic number (Z) of the element decreases by 1 because a proton is transformed into a neutron.
- Therefore, if the original atomic number is Z, after beta plus decay, the new atomic number becomes Z - 1.

3. **Change in Mass Number**:
- The mass number (A), which is the total number of protons and neutrons in the nucleus, remains unchanged during this process. This is because a proton is lost, but a neutron is gained, keeping the total count of nucleons the same.
- Thus, if the original mass number is A, it remains A after the decay.

4. **Emission of Positron**:
- During this decay process, a positron is emitted. This is a key characteristic of beta plus decay.

5. **Final Summary of Changes**:
- The final changes can be summarized as follows:
- Atomic Number (Z) changes from Z to Z - 1.
- Mass Number (A) remains unchanged.
- A positron is emitted.

### Conclusion:
In summary, during beta plus decay, the nucleus undergoes the following changes:
- The atomic number decreases by 1 (Z → Z - 1).
- The mass number remains the same (A remains A).
- A positron is emitted.