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A disc of the moment of inertia 'l(1)' ...

A disc of the moment of inertia `'l_(1)'` is rotating in horizontal plane about an axis passing through a centre and perpendicular to its plane with constant angular speed `'omega_(1)'` . Another disc of moment of inertia `'I_(2)'`. having zero angular speed is placed discs are rotating disc. Now, both the discs are rotating with constant angular speed `'omega_(2)'`. The energy lost by the initial rotating disc is

A

`1/2[(I_1+I_2)/(I_1I_2)]omega_1^2`

B

`1/2[(I_1I_2)/(I_1-i_2)]omega_1^2`

C

`1/2[(I_1-I_2)/(I_1I_2)]omega_1^2`

D

`1/2[(I_1I_2)/(I_1+I_2)]omega_1^2`

Text Solution

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The correct Answer is:
D
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