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The electric field portion of an electro...

The electric field portion of an electromagnetic wave is given by ( all variables in SI units) `E=10^(-4) sin (6xx10^(5)t -0.01x)` The. Frequency (f) and the speed (v) of electromagnetic wave are

A

`f=30/pikHz and v=1.5xx10^(7)ms^(-1)`

B

`f=90/pikHz and v=6.0xx10^(7)ms^(-1)`

C

`f=300/pikHz and v=6.0xx10^(7)ms^(-1)`

D

`f=600/pikHz and v=7.5xx10^(7)ms^(-1)`

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To find the frequency (f) and the speed (v) of the electromagnetic wave given the electric field equation \( E = 10^{-4} \sin(6 \times 10^{5} t - 0.01 x) \), we will follow these steps: ### Step 1: Identify the angular frequency (ω) and wave number (k) The general form of the electric field of an electromagnetic wave is given by: \[ E = E_0 \sin(\omega t - kx) \] From the given equation: \[ E = 10^{-4} \sin(6 \times 10^{5} t - 0.01 x) \] We can identify: - \( \omega = 6 \times 10^{5} \) radians/second (angular frequency) - \( k = 0.01 \) radians/meter (wave number) ### Step 2: Calculate the frequency (f) The frequency (f) is related to the angular frequency (ω) by the formula: \[ f = \frac{\omega}{2\pi} \] Substituting the value of ω: \[ f = \frac{6 \times 10^{5}}{2\pi} \] Calculating this gives: \[ f \approx \frac{6 \times 10^{5}}{6.2832} \approx 95500.5 \text{ Hz} \] To convert this to kilohertz (kHz): \[ f \approx 95.5 \text{ kHz} \] ### Step 3: Calculate the speed (v) The speed (v) of the wave can be calculated using the relationship: \[ v = \frac{\omega}{k} \] Substituting the values of ω and k: \[ v = \frac{6 \times 10^{5}}{0.01} \] Calculating this gives: \[ v = 6 \times 10^{7} \text{ m/s} \] ### Summary of Results - Frequency \( f \approx 95.5 \text{ kHz} \) - Speed \( v = 6 \times 10^{7} \text{ m/s} \)
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