Complete the given equations
(i) `Mg +2HNO_3(dil)rarrMg(NO_3)_2+P`
(ii) `Cu + 8 HNO_3(dil) rarr3Cu(NO_3)_2+Q+4H_2O`
(iii) `l_2+10HNO_3 (dil) rarrR +10NO_2+4H_2O`

Options

A. `NO(P),2NO_2(Q),5HIO_3(R)`
B. `H_2(P),2NO(Q),2HIO_3(R)`
C. `N_2(P)N_2(Q)HI(R)`
D. `NO_2(P)N_2O(Q)3HI(R)`

Answer

To complete the given chemical equations, we need to identify the products formed in each reaction. Let's analyze each reaction step by step.

### (i) Reaction of Magnesium with Dilute Nitric Acid
**Equation:**
\[ \text{Mg} + 2 \text{HNO}_3 \rightarrow \text{Mg(NO}_3\text{)}_2 + P \]

1. **Identify Reactants and Products:**
- Magnesium (Mg) reacts with dilute nitric acid (HNO3).
- Magnesium nitrate (\( \text{Mg(NO}_3\text{)}_2 \)) is formed.

2. **Determine the Product (P):**
- Magnesium reacts with dilute nitric acid to produce magnesium nitrate and hydrogen gas (H2).
- Thus, \( P = \text{H}_2 \).

**Completed Equation:**
\[ \text{Mg} + 2 \text{HNO}_3 \rightarrow \text{Mg(NO}_3\text{)}_2 + \text{H}_2 \]

### (ii) Reaction of Copper with Dilute Nitric Acid
**Equation:**
\[ \text{Cu} + 8 \text{HNO}_3 \rightarrow 3 \text{Cu(NO}_3\text{)}_2 + Q + 4 \text{H}_2\text{O} \]

1. **Identify Reactants and Products:**
- Copper (Cu) reacts with 8 molecules of dilute nitric acid (HNO3).
- Copper nitrate (\( \text{Cu(NO}_3\text{)}_2 \)) is formed along with water.

2. **Determine the Product (Q):**
- The reaction of copper with nitric acid produces nitrogen oxides as byproducts.
- In this case, \( Q \) is nitrogen dioxide (NO2).

**Completed Equation:**
\[ \text{Cu} + 8 \text{HNO}_3 \rightarrow 3 \text{Cu(NO}_3\text{)}_2 + 2 \text{NO}_2 + 4 \text{H}_2\text{O} \]

### (iii) Reaction of Iodine with Dilute Nitric Acid
**Equation:**
\[ \text{I}_2 + 10 \text{HNO}_3 \rightarrow R + 10 \text{NO}_2 + 4 \text{H}_2\text{O} \]

1. **Identify Reactants and Products:**
- Iodine (\( \text{I}_2 \)) reacts with 10 molecules of dilute nitric acid (HNO3).
- Nitrogen dioxide (NO2) and water are produced.

2. **Determine the Product (R):**
- Iodine reacts with nitric acid to form iodic acid (\( \text{HIO}_3 \)).
- Thus, \( R = 2 \text{HIO}_3 \).

**Completed Equation:**
\[ \text{I}_2 + 10 \text{HNO}_3 \rightarrow 2 \text{HIO}_3 + 10 \text{NO}_2 + 4 \text{H}_2\text{O} \]

### Summary of Products:
- \( P = \text{H}_2 \)
- \( Q = 2 \text{NO}_2 \)
- \( R = 2 \text{HIO}_3 \)