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The acceleration due to gravity on the s...

The acceleration due to gravity on the surface of a planet is one - fourth of the value on Earth. When a brass ball is brought to this planet , its

A

Mass is halved

B

Weight is halved

C

Mass becomes one - fourth

D

Weight becomes one - fourth

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the effects of the acceleration due to gravity on a brass ball when it is brought to a planet where the gravitational acceleration is one-fourth that of Earth. Let's go through the solution step by step. ### Step 1: Understand the given information - The acceleration due to gravity on the surface of the planet (let's call it \( g' \)) is one-fourth of that on Earth (denoted as \( g \)). - Therefore, we can express this relationship mathematically as: \[ g' = \frac{g}{4} \] ### Step 2: Analyze the mass of the brass ball - The mass of an object is defined as the amount of matter it contains and is independent of the gravitational field. - Therefore, when the brass ball is brought to the planet, its mass remains unchanged. - Let the mass of the brass ball be \( m \). Thus, the mass on Earth and the mass on the planet is: \[ m_{\text{Earth}} = m_{\text{planet}} = m \] ### Step 3: Calculate the weight of the brass ball on Earth - The weight of an object is given by the formula: \[ W = m \cdot g \] - On Earth, the weight of the brass ball is: \[ W_{\text{Earth}} = m \cdot g \] ### Step 4: Calculate the weight of the brass ball on the planet - Using the modified gravitational acceleration on the planet, the weight of the brass ball on the planet can be calculated as: \[ W_{\text{planet}} = m \cdot g' = m \cdot \left(\frac{g}{4}\right) = \frac{m \cdot g}{4} \] - This shows that the weight of the brass ball on the planet is one-fourth of its weight on Earth. ### Step 5: Conclusion - The mass of the brass ball remains constant, while its weight decreases to one-fourth of its weight on Earth. - Therefore, the correct answer is that the mass remains the same, and the weight becomes one-fourth. ### Final Answer - Mass remains constant. - Weight becomes one-fourth.
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