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The frequency for a series limit of Balm...

The frequency for a series limit of Balmer and paschen serial respectively are `f_1and f_3` if the frequency of the first line of Balmer series is then the relation between `f _1,f_2and f_3` is

A

`f_1-f_2=f_3`

B

`f_1+f_3=f_2`

C

`f_1+f_2=f_3`

D

`f_2-f_3=2f_1`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem regarding the relationship between the frequencies of the Balmer and Paschen series, we will follow these steps: ### Step-by-Step Solution: 1. **Understanding the Series Limits:** - The series limit for the Balmer series occurs when an electron transitions from an infinite energy level to \( n = 2 \). - The series limit for the Paschen series occurs when an electron transitions from an infinite energy level to \( n = 3 \). 2. **Using the Rydberg Formula:** - The Rydberg formula for the wavelength \( \lambda \) is given by: \[ \frac{1}{\lambda} = R \left( \frac{1}{n_f^2} - \frac{1}{n_i^2} \right) \] - Here, \( R \) is the Rydberg constant, \( n_f \) is the final energy level, and \( n_i \) is the initial energy level. 3. **Calculating Frequencies:** - For the Balmer series (where \( n_f = 2 \)): \[ f_1 = R c \left( \frac{1}{2^2} - \frac{1}{\infty^2} \right) = R c \left( \frac{1}{4} - 0 \right) = \frac{R c}{4} \] - For the Paschen series (where \( n_f = 3 \)): \[ f_3 = R c \left( \frac{1}{3^2} - \frac{1}{\infty^2} \right) = R c \left( \frac{1}{9} - 0 \right) = \frac{R c}{9} \] 4. **Finding the Frequency of the First Line of Balmer Series:** - The first line of the Balmer series corresponds to the transition from \( n = 3 \) to \( n = 2 \): \[ f_2 = R c \left( \frac{1}{2^2} - \frac{1}{3^2} \right) = R c \left( \frac{1}{4} - \frac{1}{9} \right) \] - To simplify \( f_2 \): \[ f_2 = R c \left( \frac{9 - 4}{36} \right) = R c \left( \frac{5}{36} \right) \] 5. **Establishing the Relationship:** - Now we have: - \( f_1 = \frac{R c}{4} \) - \( f_3 = \frac{R c}{9} \) - \( f_2 = \frac{5 R c}{36} \) - We can relate these frequencies: \[ f_1 = f_2 + f_3 \] - Rearranging gives: \[ f_1 - f_2 = f_3 \] ### Final Relation: Thus, the relation between \( f_1 \), \( f_2 \), and \( f_3 \) is: \[ f_1 - f_2 = f_3 \]
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