Dehydration of ethylene glycol in presence of concentration `H_2SO_4` will give

Options

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B.
C.
D.

Answer

To solve the question regarding the dehydration of ethylene glycol in the presence of concentrated H₂SO₄, we can follow these steps:

### Step 1: Understand the Reactants
Ethylene glycol, also known as ethane-1,2-diol, has the chemical formula C₂H₆O₂ or HO-CH₂-CH₂-OH. It contains two hydroxyl (-OH) groups.

**Hint:** Identify the structure of ethylene glycol and note the functional groups present.

### Step 2: Identify the Reaction Conditions
The reaction takes place in the presence of concentrated sulfuric acid (H₂SO₄), which acts as a dehydrating agent. Dehydration refers to the removal of water (H₂O) from the reactants.

**Hint:** Recall that concentrated H₂SO₄ is a strong acid and a dehydrating agent.

### Step 3: Dehydration Mechanism
When two molecules of ethylene glycol undergo dehydration, two water molecules are removed. The -OH groups from each ethylene glycol molecule will lose a hydrogen atom and an oxygen atom, resulting in the formation of an ether linkage.

**Hint:** Visualize the removal of water molecules from the hydroxyl groups of ethylene glycol.

### Step 4: Formation of the Product
The dehydration of two ethylene glycol molecules leads to the formation of 1,4-dioxane. The structure of 1,4-dioxane consists of a six-membered ring with two oxygen atoms at positions 1 and 4.

**Hint:** Draw the structure of 1,4-dioxane to confirm the product formed from the dehydration.

### Step 5: Analyze the Options
- Option 1: 1,4-Dioxane (Correct)
- Option 2: Ether (Incorrect)
- Option 3: 1,3-Dioxane (Incorrect)
- Option 4: Ethanol (Incorrect)

**Hint:** Compare the product formed with the given options to identify the correct answer.

### Final Answer
The dehydration of ethylene glycol in the presence of concentrated H₂SO₄ will give **1,4-dioxane**.